b^2-10b=39

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Solution for b^2-10b=39 equation:


Simplifying
b2 + -10b = 39

Reorder the terms:
-10b + b2 = 39

Solving
-10b + b2 = 39

Solving for variable 'b'.

Reorder the terms:
-39 + -10b + b2 = 39 + -39

Combine like terms: 39 + -39 = 0
-39 + -10b + b2 = 0

Factor a trinomial.
(-3 + -1b)(13 + -1b) = 0

Subproblem 1

Set the factor '(-3 + -1b)' equal to zero and attempt to solve: Simplifying -3 + -1b = 0 Solving -3 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1b = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1b = 0 + 3 -1b = 0 + 3 Combine like terms: 0 + 3 = 3 -1b = 3 Divide each side by '-1'. b = -3 Simplifying b = -3

Subproblem 2

Set the factor '(13 + -1b)' equal to zero and attempt to solve: Simplifying 13 + -1b = 0 Solving 13 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-13' to each side of the equation. 13 + -13 + -1b = 0 + -13 Combine like terms: 13 + -13 = 0 0 + -1b = 0 + -13 -1b = 0 + -13 Combine like terms: 0 + -13 = -13 -1b = -13 Divide each side by '-1'. b = 13 Simplifying b = 13

Solution

b = {-3, 13}

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